Section Quantum Mechanics Basic

Contents here are to be loaded by web lectures

Blackbody

Black body realization
A theoretical model of a blackbody. The hole is a blackbody where light goes in but does not (or at least highly unlikely to) come out.

About blackbody and blackbody radiation

Color temperature black body 800-12200K
The color of blackbody radiation at different temperature (in $K$) as appears to human eyes (which are only sensitive to a narrow range of wavelength in the electromagnetic spectrum). One could use the color of radiation to estimate of temperature of a very hot object (such as molten steel).
Furnace 2 (8510556946)
A furnace emitting an organge glow of blackbody radiation. Note that everything in the furnace and the wall of the furnace itself glow at the same color even though they are made of different materials.
Human-Infrared
Infrared image of a person. The human body is approximately a blackbody that radiates primarily in the infrared.
NASA/IPAC / Public domain
Black body
Blackbody radiation at different temperature. At short wavelength (i.e high frequency), the radiation drops to zero even though the classical theory of physics predicts an ever increasing radiation.
Darth Kule / Public domain

Difficulties with classical physics

The Difficulties with Photoelectric Effect

Photoelectric effect in a solid - diagram
The energy in light releasing electrons from atoms in the sample.

What is the photoelectric effect?

$V \gt 0$ (forward biased): photoelectrons accelerates to the right by the applied voltage, generating a current.
$V \lt 0$ (reverse biased): photoelectrons repelled backward by the applied voltage. When none of the electrons can make it to the right, the current drops to zero, and the magnitude of the applied voltage is the stopping potential $V_{stop}$.

The experiment

Number of electrons $N_e$ and cutoff frequency $f_c$
$N_e \propto I$, thus measuring the current $I$ gives the number of electrons released.

Kinetic energy of electrons $KE$ and stopping potential $V_{stop}$
$V_{stop}$ stopping all electrons means even the fastest electrons lose all their kinetic energy going against the potential. Therefore we have:
$$ KE_{max} = eV_{stop} $$
where we used the equation for work done by the electric field $W_E = -q \Delta V$ to deduce the right hand side.

Summary
Experimental observations at $f \gt f_c$
Action $KE$ $N_e$
Increase intensity No effect Increase
Increase frequency Increase Increase

Predictions from classical physics for all $f$
Action $KE$ $N_e$
Increase intensity Increase Increase
Increase frequency No effect No effect

The Photon

Before we give Einstein's full explanation of the mystery surrounding the photoelectric effect, we will first discuss one of his key insights: light consists of a stream of particles, which we call photons nowadays.

Before Einstein made the proposal in 1905, light has been convincingly "proven" to be a wave. Here were the reasonings:

Nature, however, is infinitely subtle, but she found her match in Albert Einstein. Despite the seemingly solid proofs that light is a wave, Einstein thought outside the box and realized the photoelectric effect is evidence that light can also behave like particles. We will discuss his explanation in the next section and focus on the photons in this section.

Einstein proposed that each photon at frequency $f$ carries an amount of energy:

$$ E_\gamma = h f $$
Combine with $c = f \lambda$, we can also write it as $E_\gamma = \frac{hc}{\lambda}$. Note that physicists often use the Greek letter "gamma" $\gamma$ to denote photons.

Content will be loaded by load_content.js
Content will be loaded by load_content.js

How could light be particles if we have proofs that it is a wave?

Einstein's Explanation of the Photoelectric Effect

Here is how Einstein describe light, its energy and its intensity in terms of photons:

LimaCrossroadsBluesFestival2018BallPit
A ball pit.
The ball pit analogy: throw basketballs into a ball pit to slam some little balls out of the pit. pit = sample holding electrons; ball = electron; basketball = photons; height of pit = attractive force needed to be overcome to escape.

The ball pit analogy
Ball pit Photoelectric effect
Little balls in pit Electrons bound inside sample
Basketballs Photons
Number of basketballs thrown at the pit Number of photons $N_\gamma \propto \text{intensity}$
Energy of each basketball Energy of a photon $E_\gamma = hf$
Height to the rim of the pit, $H$ Energy that must be overcome for an electron to escape, $\Phi$ (work function)
If each basketball carries too little energy, so no balls come out of the pit. You can throw more basketballs, but still no balls come out. $hf \lt \Phi$, so the photons do not carry enough energy to release the electrons. Increasing intensity (more photons) does not help.
Each basketball must carry enough energy to bring a ball up by $H$ to release the balls. The minimum frequency to release electron is $hf_c = \Phi$.
When balls come out, some are faster than others. The fastest balls are the ones closest to the surface and only need to climb up by $H$. Those deeper have to climb up more thus come out with less kinetic energy. Electrons has a range of speed. The fastest ones are the one that are the loosest (closer to the sample surface) who need to overcome energy $\Phi$. The deeper lying electrons need to overcome more so they come out with less kinetic energy. Therefore $KE_{max} = hf - \Phi$.
When the basketballs are energetic enough to release the balls, throwing more basketballs leads to more balls being released. This does not lead to the little balls moving faster when jumping out. When eletrons are released ($f \gt f_c$), increasing intensity (thus increasing $N_\gamma$) leads to more electrons released. However, the $KE$ of the electrons is unaffected.
The harder you throw the basketballs, the more energetic are the little balls coming out. Increasing $f$ increases the energy of each photon $E_\gamma = hf$. So an electron absorbing a photon will escape will more kinetic energy.
The harder you throw the basketballs, the more little balls are coming out because even the balls that are close to the bottom of the pit is shaken out by the fast basketballs. Increasing $f$ increases the energy of each photon $E_\gamma = hf$ so even the more tightly bound electrons may gain enough energy to escape.

$KE_{max}$ vs $f$ for sodium ($\Phi_{Na} = 2.46eV$) and copper ($\Phi_{Cu} = 4.70eV$).

Based on Einstein's explanation, the kinetic energy of the fastest electrons can now be understood:

$$ KE_{max} = hf - \Phi $$

The work function $\Phi$

Work Function of some metals
Metal $\Phi (eV)$
$Na$ 2.46
$Al$ 4.08
$Zn$ 4.31
$Fe$ 4.50
$Cu$ 4.70

The cutoff frequency
The photon must have energy of at least $\Phi$ to release an electron. Therefore, the lowest such frequency is: $$ \begin{eqnarray} h f_c &=& \Phi \\ \Rightarrow f_c &=& \frac{\Phi}{h} \end{eqnarray} $$ The cutoff wavelength is: $$ \begin{eqnarray} \lambda_c &=& \frac{c}{f_c} \\ &=& \frac{hc}{\Phi} \end{eqnarray} $$

Using $hc = 1242.4eV\cdot nm$
We know the following values: A quick calculation gives $hc = 1242.4eV\cdot nm$. This value is very convenient in calculations involving photoelectric effects, where energy and wavelength are usually given in $eV$ and $nm$. See the following exercise for an example.

Content will be loaded by load_content.js

Stopping potential
Recall $KE_{max} = eV_{stop}$. Since $KE_{max}$ and $V_{stop}$ differ only in $e$, they have the same numerical values when expressed in $eV$ and $V$. For example:

Content will be loaded by load_content.js
Content will be loaded by load_content.js
Content will be loaded by load_content.js
Content will be loaded by load_content.js
Content will be loaded by load_content.js
Content will be loaded by load_content.js
Content will be loaded by load_content.js

Electron Energy Level

Stylised atom with three Bohr model orbits and stylised nucleus
Planetary model (outdated) of electrons around a nucleus. The size of the nucleus is not drawn to scale and is greatly exaggerated.

The planetary model of the atoms

Bohr's hydrogen model

Simulation - Unwinding the Electron Orbit

Canvas not supported

Unwinding the Electron Orbit

[Disclaimer: This is a semi-classical (i.e. not particulary rigorous or convincing) explanation of the discrete energy levels in an atom, but it does give you a feel for the basic idea.]

Not all wavelengths are allowed on an electron orbit because the electron waves must "match up with itself" after going around one circle, otherwise destructive interference will destroy the waves. Adjust the wavelength and the radius so that the wave joins back to itself smoothly to get an "allowed" orbit.

  • $2\pi r = n \lambda$ must be obeyed.
  • de Broglie tells us momentum is $p =\frac{h}{\lambda} = \frac{nh}{2\pi r}= \frac{n\hbar}{r}$, where $\hbar = \frac{h}{2\pi}$.
  • Angular momentum is $L =rp$, therefore $L = n\hbar$.
  • This is Neils Bohr's qunatization condition on angular momentum in his (semi-classical) hydrogen model: Angular momentum only appears as integral multiples of $\hbar$.
Electron energy levels in a hydrogen atom. $E_1 = -13.6eV$ (ground state) and $E_\infty = 0eV$. At $E\gt 0$ (not shown) the electron is free and we have a continuum of energy.

Bohr's model of the hydrogen atom gives the following electron energy levels:

$$ E_n = -\frac{m_e e^4}{32 \pi^2 \epsilon_0^2 \hbar^2}\frac{1}{n^2} = -\frac{13.6eV}{n^2} $$
where $\hbar = \frac{h}{2\pi}$. Note that $E_\infty = 0eV$, when electron is freed from the nucleus and can escape from the atom.

Terminology

Content will be loaded by load_content.js
A photon is emitted when an electron falls to a lower energy level. By conservation of energy, $E_\gamma = E_i - E_f$.

Spontaneous emission

$$ hf = E_i - E_f $$
NASA Hydrogen spectrum
Emission spectrum of hydrogen. The fringes are formed by sending light through a diffraction grating.
NASA / Public domain
Hydrogen discharge tube
A high voltage across a hydrogen discharge tube is used to excite the electrons in the atoms, which in turn emits radiation when the electrons fall back to the level energy levels.
Alkali and alkaline earth metals emission spectrum
Different elements have different emission spectra because of differences in the electron energy levels.
Content will be loaded by load_content.js
Content will be loaded by load_content.js
Content will be loaded by load_content.js
Content will be loaded by load_content.js
Absorption (left): an electron moves to a higher energy level after absorbing a photon. Spontaneous emission (right): an electron releases a photon after falling to a lower energy level spontaneously.
Stimulated emission: a photon causing an electron to fall to a lower energy level, emitting an addition photon that is identical to the original photon. The energy of the original photon must be the same as the energy difference between the two energy levels.

Electron transitions
There are three types of electron transitions among energy levels:

Laser Towards Milky Ways Centre
A beam of laser creates an artificial star as a reference to correct the blurring effect of the atmosphere on images.

LASER

Electron as a wave inside a hydrogen atom

Atomic orbitals n1234 m-eigenstates
Wave functions of electrons in a hydrogen atom ("complex" version).
Hydrogen Density Plots
Cross section of the electron density in an hydrogen atom.
PoorLeno / Public domain

Simulation - Hydrogen Wave Function (3D)

Canvas not supported

Hydrogen Wave Function

  • Try $n=4$, $l=3$, $m=1$ and increase the number of points to about 30000.
  • Density of the dots represents the likelihood of locating an electron at a location.
  • Orbits are allowed only when $n>l$ and $l \geq |m|$.
  • Turn off auto rotate to use mouse control.
  • The electron wave functions in a hydrogen atom is usually written in terms of the spherical harmonic functions, $Y_l^m$. These functions are usually written in its "real" or "complex" form. The switch "Use Real Y" allows you to see the (small) difference between the two.
  • Links: static rendering of the "complex" wave functions and the "real" wave functions of hydrogen.

Beyond Hydrogen

Simulation - Spin Measurements

Canvas not supported

Spin Measurements

A lab manual based on this simulation is available here.

A simulation of the Stern-Gerlach experiment, where a particle with a magnetic moment is sent through a non-uniform magnetic field. The trajectory of the particle depends on the magnetic moment, which in turn depends on the intrinsic angular momentum (spin) it carries. Adjusting the angle on the detector in the simulation is the same as rotating the magnets in the experiment, thereby detecting the compoenent of spin along different directions.

Rotate the dials on the detector to adjust the axis of measurement. Rotate the source to change the spin of the particles emitted. $p(+)$ and $p(-)$ are the observed probability based on the accumulated counts.

  • A quantum measurements is destructive in that it changes the state of the particle. A particle leaving the detector has a different directions to that before the measurement in general.
  • The probability of observing a spin in the same direction of the dial is $p = \cos^2(\frac{\Delta \theta}{2})$, where $\Delta \theta$ is the angle between the incoming particle and the dial.
  • Even though the particles are identically produced, the observed direction depends on chance.

Things to try:

  • Click "hide info", and rotate the source to some unknown angle. Can you use the detector to figure out the angle of the source by measuring only one particle? While a single spin (a "qubit") potentially carries a huge amount of information, the universe only allows us to extract a small bit of information (whether the particle comes out on the top or the bottom exit) during a measurement. This has enormous implication to quantum computing.
  • Plot the probability on the detector for different $\Delta \theta$ to see if it matches with the theory $p = \cos^2(\frac{\Delta \theta}{2})$.

Spin

Pauli's exclusion principle

Electrons

Quantum numbers

Terminology
Shells
$n$ 1 2 3 4 5
Shell name K L M N O
Orbitals
$l$ 0 1 2 3 4 5
Orbital name $s$ $p$ $d$ $f$ $g$ $h$
Historical names: $s$: sharp, $p$: principal, $d$: diffuse, ...

See simulation below for more examples.

Simulation - Periodic Table and Quantum Numbers

Canvas not supported

Periodic Table and Quantum Numbers

  • Adjust the atomic number to see the electrons filling up the energy levels.
  • You can also click on an atomic on the periodic table.
  • The states with different values of $m$ have the same energy in the absence of a magnetic field, despite being drawn at different height.
Wp2975966
The periodic table.

Notations

Name Symbol Unit Meaning
Maximum kinetic energy of photoelectrons $KE_{max}$ $J$ or $eV$ kinetic energy of the fastest electrons released by photons
Photon energy $E_\gamma = hf$ $J$ or $eV$ energy of a single photon at frequency $f$
Work function $\Phi$ $J$ or $eV$ minimum energy required to release an electron from a material
Cutoff frequency $f_c$ $Hz$ photons below this frequency are not energetic enough to release electrons
Cutoff wavelength $\lambda_c$ $m$ photons above this wavelength are not energetic enough to release electrons
Stopping potential $V_{stop}$ $V$ magnitude of the reverse-biased applied voltage that is just enough to stop the fastest photoelectrons