Section Quantum Mechanics Basic
Action | $KE$ | $N_e$ |
---|---|---|
Increase intensity | No effect | Increase |
Increase frequency | Increase | Increase |
Action | $KE$ | $N_e$ |
---|---|---|
Increase intensity | Increase | Increase |
Increase frequency | No effect | No effect |
Before we give Einstein's full explanation of the mystery surrounding the photoelectric effect, we will first discuss one of his key insights: light consists of a stream of particles, which we call photons nowadays.
Before Einstein made the proposal in 1905, light has been convincingly "proven" to be a wave. Here were the reasonings:
Nature, however, is infinitely subtle, but she found her match in Albert Einstein. Despite the seemingly solid proofs that light is a wave, Einstein thought outside the box and realized the photoelectric effect is evidence that light can also behave like particles. We will discuss his explanation in the next section and focus on the photons in this section.
Einstein proposed that each photon at frequency $f$ carries an amount of energy:
Here is how Einstein describe light, its energy and its intensity in terms of photons:
Ball pit | Photoelectric effect |
---|---|
Little balls in pit | Electrons bound inside sample |
Basketballs | Photons |
Number of basketballs thrown at the pit | Number of photons $N_\gamma \propto \text{intensity}$ |
Energy of each basketball | Energy of a photon $E_\gamma = hf$ |
Height to the rim of the pit, $H$ | Energy that must be overcome for an electron to escape, $\Phi$ (work function) |
If each basketball carries too little energy, so no balls come out of the pit. You can throw more basketballs, but still no balls come out. | $hf \lt \Phi$, so the photons do not carry enough energy to release the electrons. Increasing intensity (more photons) does not help. |
Each basketball must carry enough energy to bring a ball up by $H$ to release the balls. | The minimum frequency to release electron is $hf_c = \Phi$. |
When balls come out, some are faster than others. The fastest balls are the ones closest to the surface and only need to climb up by $H$. Those deeper have to climb up more thus come out with less kinetic energy. | Electrons has a range of speed. The fastest ones are the one that are the loosest (closer to the sample surface) who need to overcome energy $\Phi$. The deeper lying electrons need to overcome more so they come out with less kinetic energy. Therefore $KE_{max} = hf - \Phi$. |
When the basketballs are energetic enough to release the balls, throwing more basketballs leads to more balls being released. This does not lead to the little balls moving faster when jumping out. | When eletrons are released ($f \gt f_c$), increasing intensity (thus increasing $N_\gamma$) leads to more electrons released. However, the $KE$ of the electrons is unaffected. |
The harder you throw the basketballs, the more energetic are the little balls coming out. | Increasing $f$ increases the energy of each photon $E_\gamma = hf$. So an electron absorbing a photon will escape will more kinetic energy. |
The harder you throw the basketballs, the more little balls are coming out because even the balls that are close to the bottom of the pit is shaken out by the fast basketballs. | Increasing $f$ increases the energy of each photon $E_\gamma = hf$ so even the more tightly bound electrons may gain enough energy to escape. |
Based on Einstein's explanation, the kinetic energy of the fastest electrons can now be understood:
Metal | $\Phi (eV)$ |
---|---|
$Na$ | 2.46 |
$Al$ | 4.08 |
$Zn$ | 4.31 |
$Fe$ | 4.50 |
$Cu$ | 4.70 |
Not all wavelengths are allowed on an electron orbit because the electron waves must "match up with itself" after going around one circle, otherwise destructive interference will destroy the waves. Adjust the wavelength and the radius so that the wave joins back to itself smoothly to get an "allowed" orbit.
Bohr's model of the hydrogen atom gives the following electron energy levels:
A lab manual based on this simulation is available here.
A simulation of the Stern-Gerlach experiment, where a particle with a magnetic moment is sent through a non-uniform magnetic field. The trajectory of the particle depends on the magnetic moment, which in turn depends on the intrinsic angular momentum (spin) it carries. Adjusting the angle on the detector in the simulation is the same as rotating the magnets in the experiment, thereby detecting the compoenent of spin along different directions.
Rotate the dials on the detector to adjust the axis of measurement. Rotate the source to change the spin of the particles emitted. $p(+)$ and $p(-)$ are the observed probability based on the accumulated counts.
Things to try:
$n$ | 1 | 2 | 3 | 4 | 5 |
Shell name | K | L | M | N | O |
$l$ | 0 | 1 | 2 | 3 | 4 | 5 |
Orbital name | $s$ | $p$ | $d$ | $f$ | $g$ | $h$ |
Name | Symbol | Unit | Meaning |
---|---|---|---|
Maximum kinetic energy of photoelectrons | $KE_{max}$ | $J$ or $eV$ | kinetic energy of the fastest electrons released by photons |
Photon energy | $E_\gamma = hf$ | $J$ or $eV$ | energy of a single photon at frequency $f$ |
Work function | $\Phi$ | $J$ or $eV$ | minimum energy required to release an electron from a material |
Cutoff frequency | $f_c$ | $Hz$ | photons below this frequency are not energetic enough to release electrons |
Cutoff wavelength | $\lambda_c$ | $m$ | photons above this wavelength are not energetic enough to release electrons |
Stopping potential | $V_{stop}$ | $V$ | magnitude of the reverse-biased applied voltage that is just enough to stop the fastest photoelectrons |